Question

(3x/2y^-2)^-2*18x^2y^3$(frac{3x}{2y^-2})^-2 * 18x^2y^3$

Answer 1

3x/(2y^-2)^(-2)*18x^2*y^3=(2y-2)^2* 18 x^2*y^3/(3x)^2 =

=4(y-1)^2 * 18* x^2*y^3/(9x^2)= 4(y-1)^2 * 2x^2*y*3 = 8y^3*(y-1)^2