Question

Сократите дроби:
А) 6х^2+x-2/3x+2
Б) x^2-11x+24/x^2-64
В) 3x^2+16x-12/10-13x-3x^2

Answer 1

$A) frac{6x^2+x-2}{3x+2}=frac{6(x+frac{2}{3})(x-frac{1}{2})}{3(x+frac{2}{3})}=2(x-frac{1}{2})=2x-1\B)frac{x^2-11x+24}{x^2-64}=frac{(x-8)(x-3)}{(x-8)(x+8)}=frac{x-3}{x+8}\C)frac{3x^2+16x-12}{10-13x-3x^2}=frac{3(x+6)(x-frac{2}{3})}{-3(x+5)(x-frac{2}{3})}=-frac{x+6}{x+5}$