Question

Решите уравнение:
2x^3+x^2-8x-4=0

Answer 1

2x^3+x^2-8x-4 = 0
(x+2)(x-2)(2x+1) = 0
x+2 = 0, x-2 = 0, 2x+1 = 0
x = -2, x = 2, x = $-frac{1}{2}$

Answer 2

2х^3 + х^2 - 8х - 4 = 0
Х^2( 2х + 1 ) - 4( 2х + 1 ) = 0
( 2х + 1 )( х^2 - 4 ) = 0
( 2х + 1 )( Х - 2 )( Х + 2 ) = 0
2х + 1 = 0 ==> Х = - 0,5
Х - 2 = 0 ==> Х = 2
Х + 2 = 0 ==> Х = - 2
Ответ 2 ; - 2 ; - 0,5