Question

помогите плиз
3a^2-6a+3 2a^2+12a+18

Answer 1

3a^2-6a+3 = 3(a^2 - 2a + 1) = 3(a-1)^2

2a^2+12a+18 = 2(a^2 + 6a + 9) = 2(a + 3)^2

Answer 2

a^2-18a-15=0
D=b^2-4ac=(-18)^2-4*1*(-15)=324+60=384
x1=-b-√D/2a=18-√384/2
x2=-b+√D/2a=18+√384/2