Question

Найдите значение дроби:
(72^2-23^2+94*42)/(62^2-32^2)

Answer 1

$frac{ 72^{2}- 23^{2}+94*42 }{ 62^{2}- 32^{2} } = frac{(72-23)(72+23)+94*42}{(62-32)(62+32)} = frac{49*95+94*32}{30*94}= frac{4655+3008}{30*94}= frac{7663}{2820}=2 frac{2023}{2820}$