Предмет: Алгебра, автор: Asteroid

Имеется два достаточно больших слитка сплава золота с медью. Первый слиток содержит 92% золота, а второй-80% золота. Из этих слитков надо получить 600 г сплава, содержание золота в котором 85%. Определите массу куска, который для этого необходимо взять от первого слитка.

Ответы

Автор ответа: Матов
0
в 600 г 600*0,85=510 г золота 
пусть х масса куска  взятого с первого  слитка 
тогда у масса кусака взятого с второго слитка 


 left { {{0.92x+0.8y=510
} atop {x+y=600}} right. \
\
 left { {{0.92(600-y)+0.8y=510} atop { x=600-y}} right. 

x=250
Ответ 250 г
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