Question

решить уравнение
1) arcsin x =-π/6
2) arccos (x+3)=2π/3
3) arctg (2x-1)=π/3

Answer 1

$arcsin x = -cfrac{pi}{6}\x=-cfrac{1}{2}$
$arccos (x+3)=cfrac{2pi}{3}\x+3=-cfrac{1}{2}\x=-cfrac{7}{2}$
$arctg(2x-1)=cfrac{pi}{3}\2x-1=sqrt3\x=cfrac{1+sqrt{3}}{2}$