Question

Решите уравнение:7 (2y-2)-2(3y-3,5)=9 и 21,5(3х-1)+132,4=(2,8-4х)*0,5

Answer 1

7(2у-2)-2(3у-3,5)=9
14у-14-6у+7=9
14у-6у=9-7+14
8у=16
у=16/8
у=2


21,5(3х-1)+132,4=(2,8-4х)*0,5
64,5х-21,5+132,4=1,4-2х
64,5х+2х=1,4-132,4+21,5
66,5х=-109,5
х=-109,5/66,5
х=-1 430/665=-1 86/133