Question

3x ^ 2 =-2x; 
9x ^ 2-1 = -1; 
(2x-9), (х +1) = (х-3) (х +3) 
Найдите корень: 
х ^ 2-2x +1 = 0; 
х ^ 2-4x +4 = 0;

Answer 1

$1) 3x^2=-2x , 3x^2+2x=0, x(3x+2)=0, x_1=0,x_2=-frac{2}{3}\2)9x^2-1=-1, 9x^2=0, x=0\3)(2x-9)(x+1)=(x-3)(x+3)\2x^2+2x-9x-9=x^2-9\x^2-7x=0, x(x-7)=0, x_1=0,x_2=7\4)x^2-2x+1=0,(x-1)^2=0, x=1\5) x^2-4x+4=0, (x-2)^2=0, x=2$