Question

Срочно!!! Помогите!!!

Answer 1

$x^3+2x^2-4x-8=0\x(x^2-4)+2(x^2-4)=0\(x^2-4)(x+2)=0\x^2-4=0 x+2=0\x^2_{1,2}=4 x_3=-2\x_{1,2}=^+_-2\OTBET: x_1=2;x_2=x_3=-2$