Question

Решите уравнение :(х-5)^2=3х^2-х+14

Answer 1

x^2+25-10x=3x^2-x+14
2x^2+9x-11=0
x=[-9+-sqrt(81+88)]/4=[-9+-13]/4
x1=-11/2 x2=1

Answer 2

$(x-5)^2=3x^2-x+14\x^2-10x+25=3x^2-x+14\2x^2+9x-11=0\D=81+4cdot 2cdot 11=169\ x_1=frac{-9-13}{4}=-frac{11}{2}; x_2=frac{-9+13}{4}=1$