Предмет: Математика, автор: olesyaprosviro553

выразите log7 378 через а и б если log7 3 = a и log 7 2 = b

Ответы

Автор ответа: iosiffinikov

0

378=2*27*7=2*3*3*3*7
log7 378=log7(7)+log7(2)+3*log7(3)=1+3а+б

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