Предмет: Математика, автор: redvallentina

Помогите решить задачи по геометрии, буду очень благодарна!

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Автор ответа: математик2011
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4)  В прямоугольном треугольнике высота, опущенная из вершины прямого угла на гипотенузу, есть среднее пропорциональное между проекциями катетов.
BD = √AD*DC =√4*16 = 2*4 = 8
6)
АОС и ВОД - пропорциональные треугольники (по 3 углам). Коэффициент пропорции равен 2(10:5=2)
Значит ВО = 12, СО = 4
с 5) проблемка!!??!
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