Question

решите систему уравнений {x^2+2y=-2 x+y=-1

Answer 1

x²+2y=-2
x=-1-y
(-1-y)²+2y=-2
y²+2y+1+2y=-2
y²+4y+3=0
D = b^2 - 4 * a * c = (4)^2 - 4 * (1) * (3) = 4
или
y1=−1
y2=-3