Question

Решите, плиз. 22 балла!

Answer 1

$( frac{3m-n}{3mn+ m^{2} } - frac{3m+n}{3mn- m^{2} } ): frac{4(m^{2} +n^{2}) }{ m^{2}-9n^{2}}= \ \ ( frac{3m-n}{m(3n+m)} - frac{3m+n}{m(3n-m)}): frac{4(m^{2} +n^{2})}{(m-3n)(m+3n)}= \ \ frac{(3m-n)(3n-m)-(3m+n)(3n+m)}{m(3n+m)(3n-m)} : frac{4(m^{2} +n^{2})}{(m-3n)(m+3n)}= \ \ frac{9mn-3m^{2}-3n^{2}+mn-9mn-3m^{2}-3n^{2} -mn }{m(3n+m)(3n-m)} * frac{-(3n-m)(m+3n)}{4(m^{2} +n^{2})}= \ \ - frac{-6m^{2}-6n^{2} }{4m(m^{2} +n^{2})} =[tex] frac{6(m^{2} +n^{2})}{4m(m^{2} +n^{2})} = frac{3}{2m}$

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$[tex](frac{my}{m-y} +m)* frac{ m^{2}-n^{2} }{my+y^{2} } * frac{m^{2}-y^{2}}{m+n}- frac{ m^{2}-mn+n^{2} }{m^{3} +n^{2} } + frac{1}{m+n}= \ \ frac{my+m(m-n)}{m-n} * frac{(m-n)(m+n)}{y(m+y)}* frac{(m-y)(m+y)}{m+n} - frac{m^{2}-mn+n^{2}}{(m+n)( m^{2}-mn+n^{2}) } + frac{1}{m+n}= \ \ frac{m^{2} (m-n)}{y} - frac{1}{m+n} + frac{1}{m+n} =frac{m^{2} (m-n)}{y}$

Answer 2

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