Question

Помогите ребята.
1)(2-m/2+m-m+2/m-2)÷(2+m/2-m+m-2/m+2)

Answer 1

$( frac{2-m}{2+m}- frac{m+2}{m-2}) :( frac{2+m}{2-m}+ frac{m-2}{m+2})= (frac{2-m}{2+m}+ frac{m+2}{2-m}):( frac{2+m}{2-m}- frac{2-m}{m+2})= \ \ frac{(2-m)(2-m)+(m+2)(m+2)}{(2+m)(2-m)}* frac{(2-m)(2+m)}{(2+m)(2+m)-(2-m)(2-m)}= frac{(2-m)^{2}+(m+2)^{2} }{(2+m)^{2} -(2-m)^{2} } = \ \ frac{4-4m+m^{2}+m^{2}+4m+4 }{(2+m-2+m)(2+m+2-m)}= frac{8+2m^{2} }{8m}= frac{2(4+m^{2} )}{8m}= frac{4+ m^{2} }{4m}$