Question

2^log8(5x-4)=3 срооочно,помогите

Answer 1

2^(log8(5x-4)=3
log2(2^(log8(5x-4))=log2(3)
log8(5x-4)=log2(3)

5x-4=8^(log2(3))
5x-4=27
x=27+4
x=31/5