Question

люди кто нибудь помогите решить системой
{3(х+4у)-4х=2(2х+у)
{7(х-5у)+6х=3(x+4y)+27

Answer 1

3(x+4y)-4x=2(2x+y)
7(x-5y)+6x=3(x+4y)+27
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3x+12y-4x=4x+2y
7x-35y+6x=3x+12y+27
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-x+12y=4x+2y
13x-35y=3x+12y+27
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-x+12y-4x-2y=0
13x-3x-35y-12y=27
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-5x+10y=0
10x-47y=27
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x-2y=0
10x-47y=27
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x=2y
10.2y-27y=27
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x=2y
20y-27y=27
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x=2y
-7y=27
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x=2y
y=-27/7
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x=-54/7
y=-27/7
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