Question

x+1÷√2x-1=√x-1 решите уравнение

Answer 1

x+1 = [tex] sqrt{2 x^{2} -3x+1} ; 2x² -3x+1 -x²-2x +1 =0;

x² - 5x =0; x(x- 5) =0; x=0; x =5; отв х= 5ж