Question

х+2(у+6)=3х-у РЕШИТЕ СИСТЕМУ УРАВНЕНИЙ
5х-у+3=4(х-у)

Answer 1

$left { {{x+2(y+6)}=3x-y atop {5x-y+3=4(x-y)}} right. \ left { {{x+2y+12}=3x-y atop {5x-y+3=4x-4y}} right. \ left { {{3y= 2x-12} atop {x+3=-3y}} right. \ left { {{3y-2x=-12} atop {x=-3-3y}} right. \ left { {{3y+ 2(3+3y)=-12} atop {x=-3-3y}} right. \ left { {{9y=-18} atop {x=-3-3y}} right. \ left { {{y=-2 atop {x=-3+6 }} right. \ left { {{y=-2 } atop {x= 3}} right.$