Question

2sin²2α+2cos(π/2-α)+2cos²α при α=π/6

Answer 1

2sin^2(П/3)+2sin(П/6)+2cos^2(П/6)=3/2+1+3/2=4

Answer 2

$2sin^22A+2cos(frac{pi}{2}-A)+2cos^2A=2sin^22A+2sinA+2cos^2A= \ =2(sin^2frac{pi}{3}+sinfrac{pi}{6}+cos^2frac{pi}{6})=2(frac{3}{4}+frac{1}{2}+frac{3}{4})=4$