Question

помогите алгебра 2 номера

Answer 1

• 9x^2 - 10a^3 * 6ax - 15ax^2 =
(Выносим За Скобку Общий Знаменатель "3x")
1. 3x * (3x- 10a^3 * 2a - 5ax)
(3x * (3x - (10*2) * (a^3*a) - 5ax - Поскольку "а^3*а" = "а^3*а^1", Делаем Следующее...
3x * (3x - 20 * (a^3*a^1) - 5ax
3x * (3x - 20 * a^3+1 - 5ax)
2. 3x * (3x - 20a^4 - 5ax)

• 6 * (-1(1/8)^2) + 3 * (-1(1/8)*(-1(1/2)^2) - 4 * (-1(1/8)*(-1(1/2) - 2 * (-1(1/2)^3) =
1. -6 * 1(1/8)^2 + 3 * 1(1/8)*1(1/2)^2 - 4 * 1(1/8)*1(1/2) + 2 * 1(1/2)^3
2. -1 * (6 * (1/8)^2 - 3 * (1/8)*(1/2)^2 + 4 * (1/8)*(1/2) - 2 * (1/2)^3)
3. -1 * (6 * (1/64) - 3 * (1/8)*(1/4) + 2 * (1/8) - 2 * (1/8))
4. -1 * (3 * (1/32) - 3 * (1/32) + (1/4) - (1/4))
5. -1 * ((3/32) - (3/32) + (1/4) - (1/4))
6. -1 * 0 = 0

DG_Janja

Answer 2

ясно

Answer 3

город москва

Answer 4

Много Эль Ведь!~:-)

Answer 5

да