Question

Упростить выражение

sin$frac{sin^{3}alpha-cos^{3}alpha}{1+sinalpha cosalpha}+cosalpha-sinalpha$

Answer 1

(sina-cosa)(1+sinacosa)/(1+sinacosa)+cosa-sina=sina-cosa+cosa-sina=0

Answer 2

(sin^3 x - cos^3 x) / (1+sinx*cosx) + cosx - sinx = (sinx - cosx)(sin^2 x + sinx*cosx + cos^2 x) / (1+sinx*cosx) + cosx - sinx = sinx - cosx + cosx - sinx = 0