Question

найдите решение системы уравнений способом подстановки:5х-2(у+4)=0 внизу 6(2х+3)-у=41

Answer 1

 $left { {{5x-2(y+4)=0} atop {6(2x+3)-y=41}} right. left { {{5x-2y-8=0} atop {12x+18-y=41}} right. left { {{5x-2y-8=0} atop {y=12x-23}} right. left { {{5x-2(12x-23)-8=0} atop {y=12x-23}} right. left { {{19x=38} atop {y=12x-23}} right.$

$left { {{x=2} atop {y=12*2-23=1}} right.$