Предмет: Алгебра, автор: balanar17

Помогите пожалуста!На запись под заданием не обращайте внимани.

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Автор ответа: Аноним

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1) Первые четыре числа больше предыдущего на последующие четные числа: 4, 6, 8. Следовательно пятое число будет больше четвертого на 10 и будет равно 31.

2) Второе число больше первого на 15, третье число больше второго на 31, четвертое пятое больше на 53. Идет закономерность:первая цифра числа, больше следующего числа на 2, а его вторая цифра - это начало последующей. Таким образом пятое число больше второго на 75. Это число будет 179.

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