Question

очень прошу не могу не мону

Answer 1

 

$left { {{x-frac{x+1}{3}-frac{x-2}{6}<2,} atop {2x-2leq6x+3;}} right. left { {{6x-2(x+1)-(x-2)<12,} atop {-4xleq12;}} right. left { {{6x-2x-2-x+2<12,} atop {xgeq-3;}} right. \ left { {{3x<12,} atop {xgeq-3;}} right. left { {{x<4,} atop {xgeq-3;}} right. \ -3leq x<4, \ xin[-3;4).$