Предмет: Математика, автор: НикАз

Укажите длину промежутка возрастания функции f(x)=-x³/3-х²+3х+4

 

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Автор ответа: МудрыйЕвреюшка
0

 f(x)=-x³/3-х²+3х+4

f'(x)=-x^2-2x+3

x^2+2x-3=0

D=16, x1=-3, x2=1

функция возрастает (-3;1)

значит, длина промежутка равна 4

 

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