Question

Решите неравенства:
1) 2а-4>а+3
2) 3х+2<-2х+1
3) (х-1)/4-(2х+3)/8+1<3

Answer 1

1
$2a-4\ \textgreater \ a+3$
$2a-a\ \textgreater \ 3+4$
$a\ \textgreater \ 7$

2
$3x+2\ \textless \ -2x+1$
$3x+2x\ \textless \ 1-2$
$5x\ \textless \ -1$
$x\ \textless \ -0.2$

3
$\frac{x-1}{4} - \frac{2x+3}{8}+1\ \textless \ 3$ |*8
$2(x-1)-(2x+3)+8\ \textless \ 24$
$2x-2-2x-3+8\ \textless \ 24$
$3\ \textless \ 24$
x - любое число