Question

Решение производной: y=(x2+3)(x4-1)

Answer 1

$y=(x^2+3)(x^4-1) \ y`=(x^2+3)`(x^4-1)+(x^2+3)(x^4-1)`=2x(x^4-1)+4x^3(x^2+3)=2x^5-2x+4x^5+12x^3=6x^5-2x+12x^3$

Answer 2

$y'=2x(x^4-1)+4x^3(x^2+3)=2x^5-2x+4x^5+12x^3=6x^5+12x^3-2x$