Question

Найти производную: y=arctg5x               y=x/sinx+9

Answer 1

$y=arctg5x$

$y`=frac{1}{1+(5x)^2}(5x)`=frac{5}{1+25x^2}$

$y=frac{x}{sinx}+9$

$y=frac{x`sinx-x(sinx)`}{sin^2x}=frac{sinx-xcosx}{sin^2x}$