Question

lg3x -x-log3(x+8)=log3(x+3)

Answer 1

$log_3x -x-log_3(x+8)=log_3(x+3)\ log_3left(frac{x}{x+8}right)=log_3(x+3)\ frac x{x+8}=x+3\ x=(x+3)(x+8)\ x=x^2+8x+3x+24\ x^2+10x+24=0\ D=100-4cdot24=4\ x_1=-3\ x_2=-7$