Question

найдите производную функции:

y=cosx-1/sinx

Answer 1

$y=frac{u}{v}$

$y'=frac{u'*v-v'*u}{v^2}$

$y'=frac{-sinx*sinx-cosx(cosx-1)}{sin^2x}=frac{-sin^2x-cos^2x+cosx}{sin^2x}=frac{cosx-1}{sin^2x}$