Question

Решите номер 3 есть вложение.

Answer 1

$x^4(x^2+x-3)-x(x^5+1)-3x^4+x^5=\ =x^6+x^5-3x^4-x^6-x-3x^4+x^5=2x^5-6x^4-x\ \ x=-frac{2}{9}\ \ 2*(-frac{2}{9})^5-6*(-frac{2}{9})^4+frac{2}{9}=frac{2}{9}(-frac{2*2^4}{9^4}-frac{6*2^3}{9^3}+1)=\ \ =frac{2}{9}*frac{-32-48*9+6561}{6561}=frac{2}{9}*frac{6097}{6561}=frac{12194}{59049}$