Предмет: Физика, автор: oksanapivikova

Какой максимально возможен кпд тепловой машины если температура нагревателя 250С° , а температура холодильника 30С°

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Автор ответа: dimanevedimka

кпд = (tн-tx)/tн = (250-30)/250 = 0.88 = 88%

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