Question

(-81)^-5х27^-3 разделить на 9^-15

^-степень!

Answer 1

$frac{(-81)^{-5}cdot 27^{-3}}{9^{-15}}=frac{-9^{-5}cdot 9^{-5}cdot 9^{-3}cdot 3^{-3}}{3^{-15}cdot 3^{-15}}=-frac{3^{-5}cdot 3^{-5}cdot 3^{-5}cdot 3^{-5}cdot 3^{-3}cdot 3^{-3}cdot 3^{-3}}{3^{-15}cdot 3^{-15}}=\\ =-frac{3^{(-5)cdot 4+(-3)cdot 3}}{3^{-15+(-15)}}=-frac{3^{-29}}{3^{-30}}=(-3)^{-29-(-30)}=(-3)^{1}=-3$

Answer 2

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!