Question

найти сумму геометрической прогрессии

Answer 1

q = √3 /2
b4 = 9/8
bn = b1 · q^(n - 1)
n = 4
b4 = b1 · q³
b1 = b4 : q^3 = 9/8 : (√3 / 2)³ = √3
S = b1: (1 - q) = √3 : (1 - √3 /2) = 2√3 / (2 - √3)