Question

4x^2
_____:
9x^2-y^2
X
______
3xy-y^2 упростить

Answer 1

$frac{4x^2}{9x^2-y^2}:frac{x}{3xy-y^2}=frac{4x^2}{(3x)^2-y^2}*frac{3xy-y^2}{x}=frac{4x^2*(3xy-y^2)}{x((3x)^2-y^2)}=frac{4xy(3x-y)}{(3x+y)(3x-y)}=frac{4xy}{3x+y}$