Question

найти производную функции f(x)=x^2+5/4x-5

Answer 1

$f'(x)=(frac{x^2+5}{4x-5})'=frac{(x^2+5)'(4x-5)-(x^2+5)(4x-5)'}{(4x-5)^2}=\=frac{2x(4x-5)-(x^2+5)*4}{(4x-5)^2}=frac{8x^2-10x-4x^2-20}{(4x-5)^2}=frac{4x^2-10x-20}{(4x-5)^2}$