Question

вычислите sin (-13пи/6) + cos (17пи/3) + tg (22пи/3) - ctg (37пи/4)

Answer 1

$sin(-13pi/6) = sin(-13pi/6 + 2pi) = sin(-pi/6) = -1/2$

$con(17pi/3) = cos(17pi/3 - 6pi) = cos(-pi/3) = 1/2$

$tg(22pi/3) = tg(22pi/3 - 7pi) = tg(pi/3) = sqrt{3}$

$-ctg(37pi/4)=-ctg(37pi/4-9pi)=-ctg(pi/4)= -1$

$-1/2 + 1/2 + sqrt{3} - 1 = sqrt{3} - 1$