Question

Оцените 2х + у, если 1,52 < x < 2,6 и - 3,27 < y < - 1,023

Answer 1

$1,52 textless x textless 2,6$
$- 3,27 textless y textless - 1,023$
$2x+y-$?

$1,52 textless x textless 2,6$
$1,52*2 textless 2 x textless 2,6 *2$
$3,04 textless 2 x textless 5,2$

  $3,04 textless 2 x textless 5,2$
+
$- 3,27 textless y textless - 1,023$
-----------------------------------------
$-0,23 textless 2x+y textless 4,177$