Question

уравнение 6 sin^2 x+sinxcosx=cos^2 x

Answer 1

6sin^2x-cos^2x+sinxcosx=0

6tg^2x+tgx-1=0

tgx=t

6t^2+t-1=0

t=(-1+-5)/12

t1=-1/2

t2=1/3

 

x=arctg1/3+Пk

x=arctg(-1/2)+Пk