Question

Решить логарифмическое неравенство
lg²X²+3lgX>1

Answer 1

$left { {{x geq 0} atop {4lg^2x+3lgx-1 textgreater 0}} right. \ \ 4lg^2x+3lgx-1=0 \ D=9+16=25 \ \ 1)lgx=0.25 \ x= sqrt[4]{10} \ \ 2)lgx=-1 \ x=0.1 \ \ left { {{x=[0;+b)} atop {x=(-b;0.1)(sqrt[4]{10};+b)}} right. \ \ x=[0;0.1)( sqrt[4]{10};+b)$

b=∞