Question

Найти производную:

y=(x^15+2x^6)^20

Answer 1

$y'=((x^{15}+2x^6)^{20})'=20(x^{15}+2x^6)^{19}*(x^{15}+2x^6)'= \ \ = 20(x^{15}+2x^6)^{19}*(15x^{14}+12x^5)=60(5x^{14}+3x^5)(x^{15}+2x^6)$

Answer 2

y=(x^15+2*x^6)^20

y'=(20*(x^15+2*x^6)^19)*(x^15+2*x^6)'= (20*(x^15+2*x^6)^19)*(15*x^14+12*x^5)=
=15*(x^14)*20*(x^15+2*x^6)^19+12*(x^5)*20*(x^15+2*x^6)^19 = 300*(x^14)*(x^15+2*x^6)^19 +240*(x^5)* (x^15+2*x^6)^19