Question

2-sin (-7π / 4)

3-cos (5π / 6)

4-tg (11π / 3)

5-ctg (- 3,5π )

Answer 1

2+sin(2П- П/4)= 2-№2/2= (4-№2)/2

3-сos(П- П/6)= 3+ сos П/6= 3+№3/2= (6-№3)/2

4-tg(4П-П/3)= 4+tg П/3= 4+№3

5+сtg (2П+П + П/2) = 5+ ctg (П+П/2)= 5+ 0= 5