Question

$log sqrt{6} (x-1)+log sqrt{6} (x+4)=log sqrt{6}$ 6

Answer 1

ОДЗ
x > 1

(x - 1)(x + 4) = 6 
x^2 + 3x - 10 = 0 
D = 9 + 40 = 49
x1 = ( - 3 + 7)/2 = 2
x2 = ( - 3 -  7)/2 = - 5 ∉ ОДЗ

Ответ
2