Question

Решите неравенства: (x-5)(x-1,5)<0, (x-4)(x+3)≤0

Answer 1

$(x-5)(x-1,5) textless 0\y=(x-5)(x-1.5),y=0\x=5;x=1.5\+++(1.5)---(5)+++ textgreater x$
$x$∈$(1.5;5)$

$(x-4)(x+3) leq 0\y=(x-4)(x+3),y=0\x=4;x=-3\+++[-3]---[4]+++ textgreater x$
$x$∈$[-3;4]$