Предмет: Физика, автор: nadykoval2002

У радіатор водяного опалення в кімнаті надійшло 100 кг води при t1=80°C. З радіатора вийшла вода при t2=60°С. Яку кількість теплоти отримала кімната? с=4200Дж (кг °С)

Ответы

Автор ответа: Аноним

0

Воспользуемся формулой:
Q=c*m*(t₂-t₁) = 4200*100*(80-60) = 8,4 МДж

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