Question

Упростите выражение sin^2(3pi/2 +x)+sin (x+4pi)*sin (pi/2-x)*tg (x+pi)

Answer 1

sin^2(3pi/2+x)=cos^2x
sin(x+4pi)=sinx
sin(pi/2-x)=cosx
tg(x+pi)=tgx

cos^2x+sinx*cosx*tgx=cos^2x+sin^2x=1