Question

Найдите x, заранее спасибо

Answer 1

$X^2= frac{11*(|8-6|-11/2)^2}{4*5*7*8}= frac{11*(-3,5)^2}{160*7}= frac{11*49/4}{160*7}= frac{11*7}{160*4} = frac{77}{64*10}$
$X= sqrt{ frac{77}{64*10} } = sqrt{ frac{7,7}{64} } = frac{ sqrt{7,7} }{8}$

Answer 2

$x^{2} = frac{11*(|2*4-2*3|- frac{11}{2} )^2}{(2+2)*(2+3)*(3+4)*(2+4)}$
$x^{2} = frac{11*(|8-6|- frac{11}{2} )^2}{4*5*7*6}$
$x^{2} = frac{11*(2- frac{11}{2} )^2}{4*5*7*6}$
$x^{2} = frac{11*(frac{4-11}{2} )^2}{4*5*7*6}$
$x^{2} = frac{11*(frac{4-11}{2} )^2}{4*5*6*7}$
$x^{2} = frac{11*frac{7^2}{4} }{4*5*6*7}$
$x^{2} = frac{11*7^2 }{4*4*5*6*7}$
$x^{2} = frac{11*7^2 }{4^2*5*6*7}$
$x=б sqrt{ frac{11*7^2 }{4^2*5*6*7} }$
$x=б sqrt{ frac{11*7 }{4^2*5*6} }$
$x=б sqrt{ frac{77 }{4^2*30} }$
$x=б frac{{1} }{4} sqrt{ frac{77}{30} }$