Предмет: Химия, автор: evtehovaekater

через раствор, содержащий серную кислоту, пропустили 6,72 л (н.у.) аммиака до образования средней соли. масса образовавшейся соли равна

Ответы

Автор ответа: Natasha914

H2SO4 + 2NH3 = (NH4)2SO4

n(NH3)=6.72л/22,4л/моль=0,3моль

2моль- 1 моль

0,3моль -Х

Х=0,15моль -n((NH4)2SO4)

m((NH4)2SO4)=0..15моль*120г/моль=18г

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